HMAC_SHA512 using java API

[ashlesha4gsmls]

i am changing to code to integrate HMAC_SHA512 using java API

But i get Error code 99 Transaction cannot be accepted after the new change

I am using the TEST https://secure.authorize.net/gateway/transact.dll

As mentioned i am sending the  inputstring '^' delimeter

^API LOGIN ID^TransactionID^AMT^

Please let me know what is dong wrong  and any more inforemation you want from me

[ashlesha4gsmls]

I do send the Hexa value Hex.encodeHex() API to get the Hexvalue

[Renaissance]

I’m not understanding. The hash value is submitted in your request as an http post under that name, correct? You are saying that you submit x_fp_hash in your post and the API compares it to md5?

[ashlesha4gsmls]

Originally the value in x_fp_hash(fingerprint generated was using MD5 hash, that used transaction key)

Now i am following the guide to to upgrade  to HmacSHA512 that says to use the SecurityKey .

I created a new SecurityKey.

I am creating the new value for finger print using securitykey and HmacSHA512 hashing 

This value is set in the x_fp_hash hidden field of paymentform and submitted https://secure2.authorize.net/gateway/transact.dll

The moment i submit i receive erro code 99. That means my fingerprint does not match with that of merchant. However if i revert the code old way it launches payment form.

the java code 

key is security key and data is APILOGINID^TransactiodID^timestampe^amt^

Mac sha512_HMAC = Mac.getInstance("HmacSHA512");
SecretKeySpec secret_key = new SecretKeySpec(key.getBytes("UTF-8"), "HmacSHA512");
sha512_HMAC.init(secret_key);

return Hex.encodeHexString(sha512_HMAC.doFinal(data.getBytes("UTF-8")));

Please help let me know what am i doing wrong?

FYI The old way is SIM implementation.

[ashlesha4gsmls · Accepted solution]

I got it working with new HASH the issue was conversion of the long key to byte array.

Method to convert the SecurityKey

public static byte[] hex2bin(String hex) throws NumberFormatException {
if (hex.length() % 2 > 0) {
throw new NumberFormatException("Hexadecimal input string must have an even length.");
}
byte[] r = new byte[hex.length() / 2];
for (int i = hex.length(); i > 0;) {
r[i / 2 - 1] = (byte) (digit(hex.charAt(--i)) | (digit(hex.charAt(--i)) << 4));
}
return r;
}

public String encode(byte[] key, String data) {
try {
//String hexaString = Hex.encodeHexString(key.getBytes()) ;
Mac sha512_HMAC = Mac.getInstance("HmacSHA512");
SecretKeySpec secret_key = new SecretKeySpec(key,"HmacSHA512");
sha512_HMAC.init(secret_key);

return Hex.encodeHexString(sha512_HMAC.doFinal(data.getBytes("UTF-8")));

// return new String(Hex.encodeHex(sha512_HMAC.doFinal(data.getBytes("UTF-8"))));

} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (InvalidKeyException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}

return null;
}

Thanks for the help

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